Stein Variational Gradient Descent
[Editor’s Note: This class was a part of the 2019 DFL Jane Street Fellowship.]
This guide is thanks to a many different people, all of whom took their time to give feedback, write reviews, and provide their own insights to the curriculum.
Special thanks to Cinjon Resnick, who was incredibly helpful throughout the iterations of the class, curriculum, and final notes. A special thanks as well to Professor Qiang Liu, who took the time to help shape the curriculum.
Thank you to Calvin Woo, Sanyam Kapoor, Thomas Pinder, Swapneel Mehta, and Avital Oliver for useful contributions to this guide, as well as countless insights during our discussions.
A special thanks to the many outside guests who offered to provide their time, including Dilin Wang, Tongzheng Ren, and Haoran Tang.
Finally, thank you to all my fellow students who attended the recitations and provided valuable feedback.
Why
Stein’s Method is a powerful statistical method, one that is at the disposal (and the focus) of many statisticians today. Recently, Stein’s Method has made its way into machine learning and has already proved to be a fruitful research area. Stein’s Method has deep connections to many machine learning problems of interest, and by the end of this guide, you should be able to understand the relevant mathematics behind this powerful tool.
1 Basics Behind Kernelized Stein Discrepancy
Motivation: Before jumping into all the math and methodology, we have to be able to understand the basics of what’s going on. Most importantly, we will review the basics of measure theory and reproducing kernel hilbert spaces. Measure theory allows us to understand the notion of discrepancy measures between distributions, which we will use later on to quantify the difference between two arbitrary distributions of interest. Our other topic, Reproducing Kernel Hilbert Spaces (RKHS), will serve as the connection between measure theory and a practical machine learning algorithm. With RKHS, we will be able to define and optimize intractable measures which previously, were only useful for theoretical analysis or a restrictive class of functions. These two together set the foundation for defining a tractable Kernelized Stein Discrepancy, which serves as the driving factor behind Stein Variational Gradient Descent.
Topics:
 Measure Theory
 Kernels
 Reproducing Kernel Hilbert Space
 Machine Learning Basics
Notes: In this class, we went over the basic mathematical concepts we will need throughout the rest of the curriculum. See here for the notes in Colab or here for the PDF.
Required Reading:
 Reproducing Kernel Hilbert Spaces Tutorial, Section 1  3.
 A gentle introduction to Measure Theory (Chandalia).
Optional Reading:
 Slides on RKHS from Arthur Gretton.
 CS231n’s Numpy and Python Tutorial.
 CS229’s Linear Algebra Refresher.
 Xavier Bourret Sicotte’s Blog on Kernels and Feature Maps.
Questions:
 “However, Cauchy sequences are not the same as convergent sequences”, but a property of Cauchy sequences is that they are bounded. What’s the difference?
Solution
Convergent sequences have a limit, but Cauchy sequences are only required to be bounded. But what exactly does bounded mean? Here's a proof that shows that they are bounded, which might shed some light on the definition itself:
a. There exists \(N\) such that \(a_n  a_m < 1 \quad \forall m, n \geq N\) (Property of Cauchy Sequence iterates getting closer)
Therefore the Cauchy sequence \(\{ a_n \}\) is bounded \(\square\)
b. \(\implies \forall n \geq N, a_n  a_N < 1\)
c. \(a_n \in (a_N  1, a_N + 1) \forall n \geq N\). (\(n \geq N\) is bounded)
d. Since the sequence is \(n < N\) is finite (since \(N\) is finite), it is also bounded.  “The open interval (0, 1) is not complete whereas the closed interval [0, 1] is complete.” Why? Can we use this example to get a intuitive definition of complete?
Solution
Intuitively, a space is complete if there are no "points missing" from it (inside or at the boundary). For instance, the set of rational numbers is not complete, because e.g. \(\sqrt{2}\) is "missing" from it, even though one can construct a Cauchy sequence of rational numbers that converges to it. More information can be found at Wikipedia: Complete Metric Space.
 Explain the difference between a Banach and Hilbert Space. Is every Hilbert space a Banach space?
Solution
A Banach space is a vector space in which each vector has a nonnegative length, or norm, and in which every Cauchy sequence converges to a point of the space. Also known as complete normed linear space. A Hilbert space is a Banach space with inner product, which defines the norm.
 In Machine Learning, kernels can be thought of as a “dot product” (a kind of similarity score) in highdimensional space. Why would this be useful? Given a feature map, do we always have a corresponding kernel? Given any kernel, can we always explicitly write out the elements of the corresponding feature map?
Solution
Kernels (and the corresponding kernel trick) allow us to compute similarities in highdimensional space without explicitly writing out and computing the dot product. However, not ever feature map corresponds to a kernel; there are certain properties a kernel must have, and not every feature map imbues it with those properties. Likewise, given a kernel, it may be the case that we can never write out (explicitly) the corresponding feature map. A good example of this is the popular exponential kernel.
 Assume that we just need the loglikeihood in many machine learning tasks so that we can compute \(KL(qp)\) , and iteratively fit our model \(p\) to the underlying, generating data distribution \(q\). Why is this already too large of an assumption (“We assume that we have the ability to calculate the loglikelihood under the model that we specify”)?
Solution
The dreaded normalization constant! Most models we see will give an unnormalized likelihood, and the normalization constant (which we will see in a few weeks, often denoted as \(Z\)) is intractable to compute. We need the normalization constant to bring a probability function to a probability density function.
 What is the use of MonteCarlo methods in machine learning?
Solution
They are a way to estimate quantities in the presence of complex, manyrandomvariable situations. They do so by repeatedly generating (via simulation) instances from which they estimate the quantities.
 Explain the reproducing property in your own words.
Solution
Sanyam Kapoor's answer from our class was: "Every feature map is a linear combination of the full Hilbert space weighted by the kernel evaluations."
2 Stein’s Method
Motivation: Most of the theory we will see in this curriculum builds off the general theoretical framework of Stein’s Method, a tool to obtain bounds on distances between distributions. In Machine Learning (as we shall later see), distances between distributions can be used to quantify how well (or poorly) a model is at approximating a certain distribution of interest. We shall start from Stein’s Identity and Operator, while explaining their theoretical significance and working through some proofs to get an understanding of some terms (Stein’s Method, Stein’s Discrepancy) we’ll see in the coming weeks. Lastly, we will discuss why Stein’s Method has historically been a theoretical tool, and hint at how ideas from Week 1 (particularly RKHS) can be used in combination with Stein’s Method to build the tractable discrepancy measure at the center of Week 3’s discussion.
Topics:
 Stein’s Method
 The Stein Operator
 Stein Equation
 Stein’s Identity
Notes: In this class, we discussed the theoretical concepts behind Stein’s method, and discussed different ways to interpret the core ideas. See here for the notes in Colab or here for the PDF.
Required Reading:
Optional Reading:
Questions:
 Prove Stein’s Identity for a standard Gaussian random variable \(Z\).
Solution
Recall that Stein's Identity tells us that for a unitnormal random variable \(Z\) (i.e \(Z \sim \mathcal{N}(0, 1)\)): $$ \mathbf{E}f'(Z) = \mathbf{E}Zf(Z)$$ for all absolutely continuous functions \(f\) with \( \mathbf{E}[f'(Z)] < \infty \). To start, we state, without proof, that the density function of the unit normal Gaussian: $$ p(z) = \frac{1}{\sqrt{2\pi}}e^{\frac{z^2}{2}} $$ satisfies \( zp(z) = p'(z) \). For some normal \(Z\), we can break the left hand side of the original identity into two integrals: $$\mathbf{E}f'(Z) = \int_0^\infty f'(z)p(z)dz + \int_{\infty}^0 f'(z)p(z)dz $$ For each lefthand side integral, we use Fubini's Theorem: $$ \int_0^\infty f'(z)p(z)dz = \int_0^\infty f'(z) \int_z^\infty yp(y)dydz $$ $$ \int_0^\infty f'(z)p(z)dz = \int_0^\infty \int_z^\infty f'(z)yp(y)dydz $$ $$ \int_0^\infty f'(z)p(z)dz = \int_0^\infty \int_0^y f'(z)yp(y)dzdy $$ Leading us to our final integral: $$ \int_0^\infty f'(z)p(z)dz = \int_0^\infty [f(y)  f(0)] yp(y)dy $$ For the second integral, it evaluates to \( \int_{\infty}^0 [f(y)  f(0)] yp(y)dy \) When we combine each individual result, we get: $$ \mathbf{E}f'(Z) = \mathbf{E}Z[f(Z)  f(0)] = \mathbf{E}Zf(Z)$$ which proves the forward direction.
 Explain why Stein’s Identity is useful.
Solution
Stein's Identity in the converse as well; if the identity holds, we can conclude the random variable, which we call \(W\), is also normal. However, if the two quantities in Stein's Identity are approximately equal, then Stein's Identity also lets us conclude that \(W\) is also approximately normal. Stein's Identity and Method are used to quantify this "approximately" term, which we briefly discuss below. Probability metrics (between two random variables \(X\) and \(Y\)) take the general form of: $$d(X, Y) = \sup_{h \in \mathcal{H}}  \mathbf{E}h(X)  \mathbf{E}h(Y) $$ for some class of functions \( \mathcal{H} \). We normally want to bound the distances between the corresponding distribution functions \(P \) and \(Q \), but that choice is less important for this brief discussion. When we choose different classes of functions, we can recover various distances that we often use (in machine learning) to compare probability distributions, such as the Kolmorgov or Wasserstein distance. We get to the Stein Discrepancy by measuring the distance between \(W\) to our standard normal \(Z\) via: $$ \mathbf{E}h(W)  \mathcal{N}h $$ where \(\mathcal{N}h = \mathbf{E}h\) for \(h \in \mathcal{H}\). Stein's Identity tells us that the discrepancy can also be measured by: $$ \mathbf{E}[f'(W)  Wf(W)]$$ which, when we evaluate at \(w\), gives us the Stein Equation: $$ f'(w)  wf(w) = h(w)  \mathcal{N}h $$ Since we're trying to bound: \(\mathbf{E}h(W)  \mathcal{N}h\), we can now instead bound the LHS, which turns out to be a lot easier once we account for all of the boundary conditions.
3 Kernelized Stein Discrepancy
Motivation: The main theoretical meat comes from a single 2016 paper titled Kernelized Stein Discrepancy (KSD). KSD takes the powerful Stein’s Identity, and uses RKHS theory to define a tractable discrepancy between a ground truth distribution and samples from an arbitrary one. Most importantly, KSD defines a discrepancy function that does not involve calculating the normalizing constant, allowing it to be much more widely applicable in practical tasks. We will discuss the difference between likelihoodfree and likelihoodbased methods in machine learning, how this normalization constant proves to be problematic in machine learning, and how KSD allows us to sidestep this issue with a new, tractable discrepancy. KSD will serve as the launch pad for the algorithm at the focus of this curriculum, Stein Variational Gradient Descent.
Topics:
 A Stein Discrepancy
 Goodness of Fit
 Tractable Optimization of the Stein Discrepancy
Notes: In this class, we worked through the Kernelized Stein Discrepancy paper, focusing on the optimization and use cases of such a method. See here for the notes in Colab or here for the PDF.
Required Reading:
 A Short Introduction to Kernelized Stein Discrepancy.
 ICML 2015 Slides on KSD.
 Kernelized Stein Discrepancy.
 What is Maximum Mean Discrepancy?.
Optional Reading:
Although we focus on the work leading up to Stein Variational Gradient Descent, this week’s optional reading provides historical context on how Stein’s Method was introduced into the context of machine learning.
 Measuring Sample Quality with Stein’s Method.
 A Kernel Test of Goodness of Fit
 Measuring Sample Quality with Kernels
The first reference, from Gorham and Mackey, introduced the notion of a Stein Discrepancy. Kernelized Stein Discrepancy, the paper of focus for this week, built upon that idea with kernels, enabling the use of kernel functions in the Stein Discrepancy. The latter two references are also works that independently developed kernelbased Stein Discrepancies.
Questions:
 What determines the choice of kernel in KSD?
Solution
Since KSD requires an RKHS for optimization, the kernel must be positive definite. However, whenever given a positive definite kernel \(K\), we can always build an associated RKHS as follows.
If we take \(H\) as the Hilbert space of functions \(f: \mathcal{X} \rightarrow \mathbf{R}\) defined on some set \(\mathcal{X}\) with some inner product \( \langle \cdot, \cdot \rangle_H \) defined on \(H\), then we can define the evaluation functional \(e_x: H \rightarrow \mathbf{R}\) as \(f \rightarrow e_x(f) = f(x) \).
Using the above definitions, our space \( H\) is an RKHS iff the evaluation functionals are continuous. As we saw in the notes, we call the given kernel \(K\) a reproducing kernel if:
1. \(K(x, \cdot), \; \forall x \in \mathcal{X}\)
2. \(\langle f, K_x \rangle = f(x) \; \forall f \in H, \forall x \in \mathcal{X}\).
Thus, every reproducing kernel \( K\) induces a unique RKHS given the kernel is positive definite.
Excitingly, in the context of machine learning, positive definite kernels themselves can be defined in terms of inner products. Therefore, we can generate arbitrary kernels and RKHS with some feature map \( \Phi: \mathcal{X} \rightarrow \mathcal{F}\) where feature space \( \mathcal{F}\) is a Hilbert space with some inner product \( \langle \cdot, \cdot \rangle \).
4 Stein Variational Gradient Descent
Motivation: Stein Variational Gradient Descent (SVGD) is a popular, nonparametric Bayesian Inference algorithm that’s been applied to Variational Inference, Reinforcement Learning, GANs, and much more. This week, we study the algorithm in its entirety, building off of last week’s work on KSD, and seeing how viewing KSD from a KLDivergenceminimization lens induces a powerful, practical algorithm. We discuss the benefits of SVGD over other similar approximators, and look at a practical implementation of the algorithm.
Topics:
 Stein Variational Gradient Descent
 Implementing the Algorithm
Notes: In this class, we go over the core paper, Stein Variational Gradient Descent. At the end of the notes, we provide link to implementations in a variety of different languages. See here for the notes in Colab or here for the PDF.
Required Reading:
Optional Reading:
Questions:
 Compare and contrast the method shown here and MCMC. What are some advantages MCMC still has over SVGD?
Solution
Below are some ideas we discussed in our class.
1. SVGD requires a compact subspace \( \mathcal{X} \), and as noted here in Chen '19, requires the number of particles to be fixed apriori.
2. SVGD has a lot less theoretical understanding compared to MCMC (which, is potentially due to the recency of the result). SVGD has had analysis done in the infiniteparticle regime, but minimal work done in finite particle scenarios (an example of such work can be found here. A concern of theoretical analysis is the complexity of analyzing the interacting particle updates, so the works covered here either view it from a dynamical systems / differential equation perspective (which concerns the smooth transformation of density), or discuss the properties of the final particles, regardless of how they were algorithmically attained.
3. SVGD still seems to collapse in highdimensional spaces, leading to exciting new research in why this occurs and ideas on how to get around it.  Prove that the discrepancy in Equation 3 of the Stein Variational Gradient Descent Paper only equals 0 when (p) and (q) are equal.
Solution
Recall the operator definition of Stein's Identity: $$ \mathbf{E}_p[\mathcal{A}_pf(x)] = 0$$ If \( p \neq q \), we get \( \mathbf{E}_q[\mathcal{A}_pf(x)] \) for some choice of function \( f \). We can expand this to: $$\mathbf{E}_q[\mathcal{A}_pf(x)]  \mathbf{E}_q[\mathcal{A}_qf(x)]$$ Recalling the full definition of the operator: $$\mathcal{A}_pf(x) = \mathbf{E}_p[s_p(x)f(x) + \nabla_x f(x)] = 0$$ where score function \( s_p(x) \) is just \( \nabla_x \log p(x) \), we are left with $$\mathbf{E}_q[(s_p(x)  s_q(x))f(x)]$$ This means unless \(p = q \rightarrow s_p(x) = s_q(x) \; \forall x \in \mathcal{X} \), we can always find some function \(f\) for which the above quantity is nonzero.

Implement SVGD in your favorite language (see the notes for links to different implementations). Then, let’s take a look at the role of the kernel in SVGD:

Remove the repulsive kernel term and observe how particles collapse to modes.

Remove the kernel’s contribution in the first term.
What happens?

5. SVGD as Gradient Flow
Motivation: SVGD as Gradient Flow is one of the first papers that analyzes the dynamics and theoretical properties of SVGD. This paper covers an incredible amount of seeminglydisparate topics, connecting them in a succinct explanation. Due to the relative difficulty of the material, especially the necessary background, the attached notes are selfcontained and should be read alongside the paper.
Topics:
 Large Sample Regime of SVGD
 Continuous Time Analysis of SVGD
 Optimal Transport, Wasserstein Distances, and Differential Geometry
 SVGD as a Gradient Flow
Notes: In this class, we try to understand the geometric implications of SVGD. The notes are structured relatively differently  with the amount of background needed, relevant material is introduced inline. As a result, the ideal way to understand this week requires reading the notes alongside the paper, using the background sections to understand the concepts and their connections within the paper. See here for the notes in PDF.
Required Reading:
6. Stein in Reinforcement Learning
Motivation: One of the most exciting use cases of SVGD is in reinforcement learning, due to its connection to maximum entropy reinforcement learning. This week, we study two key techniques in reinforcement learning that use SVGD as the underlying mechanism. In reinforcement learning, the target distribution is not known, so we derive gradient updates to our parameters using policy gradients. As we derive the gradient estimators in the maximumentropy framework of reinforcement learning, we will start to see what benefits SVGDbased methods have. In particular, we will focus on the exploreexploit tradeoff, as well as normalization constants for intractable distributions, and see how SVGD helps us get around complicated problems regarding both.
Topics:
 Reinforcement Learning
 Explore vs. Exploit
 Maximum Entropy Reinforcement Learning
Notes: In this class, we look at the application area of reinforcement learning, and see how the diversity induced by SVGD (and its connection to maxmimum entropy reinforcement learning) generates stronglyexploring policies. See here for the notes in Colab or here for the PDF.
Required Reading:
Optional Reading:
 A Long Peek into Reinforcement Learning.
 Learning to Draw Samples with Amortized SVGD  Same as W4.
 Soft QLearning BAIR Blogpost.
 Learning SelfImitating Diverse Policies (an improved SVPG).
 Bayesian MAML.
Questions:
 What are some of the issues with using the RBF kernel when comparing RL policies? Is parameter space appropriate for comparing policies?
Solution
While it works in practice, the networks used for particles in the original SVPG paper were reasonably small. With larger numbers of parameters (i.e which are necessary when working with imagebased observations), parameterbased discrepancies start to make even less sense. This is one of two core ideas that drove the formulation of the SelfImitating Diverse Policies paper, seen as Resource 4 in Optional Reading.

In SVPG, the introduction of a prior (and priors in RL) is one active area of research. To incorporate priors in this framework, what “space” does the prior need to be over?
Solution
SVPG incorporates a prior over \(q \), which is actually a prior over the distribution of particle parameters \(\theta\). Since this space is uninterpretable, the prior term is set to be a constant, generating an "improper" prior that, in most use cases, can get dropped out of the optimization. Even if you were to use an old set of particles as a prior, the term is basically unusable, because in order to estimate the density of \(q\), you'd need to fit highdimensional ( \( d = \mathbf{R}^{\theta} \)) kerneldensity estimators. In addition, usually the number of particles used is much less than the number of parameters each has, making the density estimation an illposed problem.
 With the code implementation linked in the notes (or, your own), ablate on the architecture of each SVPG particle. What types of behavioral differences do you see in the different policies as you increase or decrease? Try adding a second layer instead; for example, how does a 2layer, 200 neuronperlayer network compare to a singlelayer, 400 neuron particle?